Great news, Simon, and glad that Moe was able to help. He must havea better memory, or more organized files than I ever had. It would be wonderful if you could document the algorithm that you willuse

So, Spoke with Moe, I now know all I must do when I restart programming. Simon Brown, G4ELI https://www.sdr-radio.com

Hi Conrad, Thanks for sharing that. I also have one on order. Some rumors have been circulating around hinting that it might be delayed. I am sure they will get it figured out.

Conrad, Thank you I figured this question would come up. The K4 does have a beautiful display and I do use it. I have a video capture card and route the HDMI port on the K4 to my PC and then can use

I received this from Apache regarding shipment of the 14-bit Hermes that several users are waiting for. 73 Conrad PA5Y From: support@... <support@...> Sent: 19 March 2022 12:56 To: Conrad

Hello Fred. I must ask why you use an RSP2Pro and SDRC when you already have an SDR based radio with a waterfall? Surely the K4 has a much better receiver. Is the K4 waterfall poor? I use SDRC

Anyone using the Elecraft K4 with SDR-Consloe? I'm have a small problem. When I have SDR-Console running then I start the K4 up it puts the K4 into transmit for a few seconds. When I start the K4

Hi Nick, I’ll ask Moe. Simon Brown, G4ELI https://www.sdr-radio.com

That would be my understanding also, and easy to test inSpectraVue. I've just played back a NetSDR file in Continuum mode, 1300kHz span ofthe MW band, using 2048 point FFT and 2097152 point

I wouldn't think that the RBW matters for this. Just sum all X bins. If RBW is smaller then X will be bigger and there will be less power in each bin. Sum of the bins will be the same for a given

Figure one signal is present, a unit gain (0 dBfs) sinewave. Without shaping it will appear in one or two bins ideally. You take the power level for all bins within the bandwidth Y and

Typo. Given: Center frequency & bandwidth with have a count of FFT bins = X (values in dBm) Resolution bandwidth = Y Hz What’s the formula for the actual continuum value when these X bins

So, Given: Center frequency & bandwidth è Count of FFT bins = X (values in dBm) Resolution bandwidth = Y Hz What’s the formula for the actual continuum value when these X bins are used?

Hello Simon, I really appreciate you adding this feature. I do have SpectraVue and an SDR-IP and in the past like Charles I used SDRC with Perseus and the IQ outputs as inputs for SpectraVue. Very

Heh heh - processing in the frequency domain makes a lot of this easy. The chief issue is the current FFT resolution compared the bandwidth you want. The "cheap, quick, and dirty"

Hi. I would like to add two more points to the short spec for the Continuum Mode function: Possibility to set a smaller BW for the measurement than the sampled BW and to set where this BW shall be in

Not at all. Glad you found the positive saying! The one I came to think about mirrors the Scandinavian "Jantelagen" and misery and gloom. Raising a finger of warning, do not indulge! För mycket

Indeed, Possible when I have time. Simon Brown, G4ELI https://www.sdr-radio.com

For satellite use, I find Mercator projection helpful ("round" footprints). Perhaps something for the future? David -- SatSignal Software - Quality software for you Web:

Good answer Curt. I might have been the only one confused. On Tuesday, March 15, 2022, 04:58:36 PM CDT, Curt Faulk